(1/((5x-1)^2))+(1/(5x-1))-12=0

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Solution for (1/((5x-1)^2))+(1/(5x-1))-12=0 equation:


D( x )

5*x-1 = 0

(5*x-1)^2 = 0

5*x-1 = 0

5*x-1 = 0

5*x-1 = 0 // + 1

5*x = 1 // : 5

x = 1/5

(5*x-1)^2 = 0

(5*x-1)^2 = 0

5*x-1 = 0 // + 1

5*x = 1 // : 5

x = 1/5

x in (-oo:1/5) U (1/5:+oo)

1/((5*x-1)^2)+1/(5*x-1)-12 = 0

1/((5*x-1)^2)+(1*(5*x-1))/((5*x-1)^2)+(-12*(5*x-1)^2)/((5*x-1)^2) = 0

1*(5*x-1)-12*(5*x-1)^2+1 = 0

5*x-300*x^2+120*x-12 = 0

125*x-300*x^2-12 = 0

125*x-300*x^2-12 = 0

125*x-300*x^2-12 = 0

DELTA = 125^2-(-300*(-12)*4)

DELTA = 1225

DELTA > 0

x = (1225^(1/2)-125)/(-300*2) or x = (-1225^(1/2)-125)/(-300*2)

x = 3/20 or x = 4/15

(x-3/20)*(x-4/15) = 0

((x-3/20)*(x-4/15))/((5*x-1)^2) = 0

((x-3/20)*(x-4/15))/((5*x-1)^2) = 0 // * (5*x-1)^2

(x-3/20)*(x-4/15) = 0

( x-3/20 )

x-3/20 = 0 // + 3/20

x = 3/20

( x-4/15 )

x-4/15 = 0 // + 4/15

x = 4/15

x in { 3/20, 4/15 }

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